4x^2+19x+38=0

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Solution for 4x^2+19x+38=0 equation: 



4x^2+19x+38=0

a = 4; b = 19; c = +38;
Δ = b2-4ac
Δ = 192-4·4·38
Δ = -247
Delta is less than zero, so there is no solution for the equation

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